X^2+25x-90=0

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Solution for X^2+25x-90=0 equation: 



X^2+25X-90=0

a = 1; b = 25; c = -90;
Δ = b2-4ac
Δ = 252-4·1·(-90)
Δ = 985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{985}}{2*1}=\frac{-25-\sqrt{985}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{985}}{2*1}=\frac{-25+\sqrt{985}}{2}
$

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